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ABC is a given triangle. A straight line...

ABC is a given triangle. A straight line EF is drawn parallel to BC. It cuts AB at E and AC at F. If area of AEF is one third area of quadrilateral EBCF then `EB:AB` is

A

`1:2`

B

`1:sqrt(2)`

C

`1:sqrt(3)`

D

`1:9`

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The correct Answer is:
To solve the problem, we will follow these steps: ### Step 1: Understand the Given Information We have triangle ABC, and a line EF is drawn parallel to BC, intersecting AB at E and AC at F. The area of triangle AEF is given to be one-third of the area of quadrilateral EBCF. ### Step 2: Set Up the Relationship Between Areas Let the area of triangle AEF be denoted as \( A_{AEF} \) and the area of quadrilateral EBCF as \( A_{EBCF} \). According to the problem, we have: \[ A_{AEF} = \frac{1}{3} A_{EBCF} \] ### Step 3: Express the Area of Quadrilateral EBCF The area of quadrilateral EBCF can be expressed as: \[ A_{EBCF} = A_{ABC} - A_{AEF} \] where \( A_{ABC} \) is the area of triangle ABC. ### Step 4: Substitute the Area Relationship Substituting the expression for \( A_{EBCF} \) into the area relationship gives us: \[ A_{AEF} = \frac{1}{3} \left( A_{ABC} - A_{AEF} \right) \] ### Step 5: Solve for \( A_{AEF} \) Multiplying both sides by 3 to eliminate the fraction: \[ 3A_{AEF} = A_{ABC} - A_{AEF} \] Adding \( A_{AEF} \) to both sides: \[ 4A_{AEF} = A_{ABC} \] Thus, we can express the area of triangle AEF in terms of the area of triangle ABC: \[ A_{AEF} = \frac{1}{4} A_{ABC} \] ### Step 6: Use the Similarity of Triangles Since EF is parallel to BC, triangles AEF and ABC are similar by the Angle-Angle (AA) criterion. Therefore, the ratio of their areas is equal to the square of the ratio of their corresponding sides: \[ \frac{A_{AEF}}{A_{ABC}} = \left( \frac{AE}{AB} \right)^2 \] Substituting the area relationship: \[ \frac{1}{4} = \left( \frac{AE}{AB} \right)^2 \] ### Step 7: Solve for the Ratio of Sides Taking the square root of both sides: \[ \frac{AE}{AB} = \frac{1}{2} \] This implies: \[ \frac{EB}{AB} = 1 - \frac{AE}{AB} = 1 - \frac{1}{2} = \frac{1}{2} \] ### Step 8: Final Ratio Thus, the ratio \( EB:AB \) is: \[ EB:AB = 1:2 \] ### Conclusion The final answer is \( EB:AB = 1:2 \). ---
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