If the system is left from rest find the time taken by the 8kg block to reach the ground.

In the figure-2.216, the masses A and B are of 4kg and 12 kg respectively. When the system is released from rest, find the time after which the block B will hit the ground.

A balloon starts rising from the ground with a constant acceleration of 1.25m//s^(2) . After 8 s, a stone is released from the balloon. Find the time taken by the stone to reach the ground. (Take g=10m//s^(2) )

A balloon starts rising from the ground with an acceleration 2 ms^(-2) . After 5 second , a stone is released from the ballooon. Find the time taken by the stone to reach the ground after its release and total height attained by ballooon when stone reaches the ground. Take g==10 ms^(-2) .

A balloon reses from rest on the ground with constant acceleration g // 8. A stone is dropped from the balloon when the balloon has resen to a height of (H). Find the time taken by the stone to reach the ground.

A ball is thrown vertically upward with a velocity u from the top of a tower. If it strikes the ground with velocity 3u, the time taken by the ball to reach the ground is

A helicopter rises from rest on the ground vertically upwards with a constant acceleration g. A food packet is dropped from the helicopter when is at a height h. The time taken by the packet to reach the ground is close to [ g is the acceeration due to gravity] :

A block A (mass 4M) is placed on the top of a wedge block B of base length l (mass=20M) as shown in figure. When the system is released from rest. Find the distance moved by the block B till the block A reaches ground Assume all surfaces are frictionless.

A block slides down from top of a smooth inclined plane of elevation ● fixed in an elevator going up with an acceleration a_(0) The base of incline hs length L Find the time taken by the block to reach the bottom .

A balloon is ascending at the constant rate of 9.8 m//sec at a height of 98 m above the ground a packet is dropped from it. If time taken by the packet to reach the ground is (1 + sqrt(3lambda))sec . Find lambda . (Use g = 9.8 m//s^(2) )