The number of ways in which 10 persons can sit round a circular table so that none of them has the same neighbours in any two arrangements, is

Options

A. 9!
B. `1/(2) 9!`
C. 10!
D. `1/(2) 10!`

Answer

A

Explanation

10 persons can sit round a circular table in `9!` ways. But here clockwise and anticlockwise orders will give the same neighbours. Hence the required number of ways = `1/(2) 9!`