There are n different books and p copies of each in a library. The number of ways in which one or more than one book can be selected is -

Options

A. `p^(n) + 1`
B. `(p+1)^(n) - 1`
C. `(p+1)^(n) - p`
D. `p^(n)`

Answer

B

Explanation

Total cases = p + 1 (if selected or not)
Required number of ways`= (p+1)^(n) - 1`
Ans.[2]