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Microscopic Form of OHM Law...

Microscopic Form of OHM Law

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Using the microscopic form of Ohm's law (J=sigma E) , prove that conductivity of a metal can be written as sigma="ne"mu . Here n is the number of free electrons per unit volume and mu is mobility of free electrons . In case of semiconductors there are two types of conduction particles, one is free electrons and the other is known as a hole. Charge on the hole may be assumed to be equal and opposite of that on electron. The number density of free electrons and holes in the semiconducting material are n and p respectively. Assuming mu_e and mu_h as mobility of free electrons and holes respectively , write the exopression of conductivity of the semiconducting material.

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Ohm's law

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