Application of Potentiometer #!#Measure unknown EMF of a cell #!#Measuring internal resistance of a cell

The emf of a cell having internal resistance is

To Measure Internal Resistance Of A Cell|Questions

Name the device used for measuring the internal resistance of a secondary cell.

E.m.f. of a cell is measured in

In an experiment to find the internal resistance of a cell by a potentiometer, a balance was obtained for 50 cm length of the potentiometer wire, with a cell of e.m.f. 2V. When the cell was shunted by a resistance of 2 Omega , the balancing length of the potentiometer wire was 40 cm. What was the internal resistance of the cell ?

A cell of emf (E) and internal resistance (r) is balanced across (l) length of potentiometer wire. If another cell of emf 2E and internal resistance (2r) is connected in parallel to the first cell , then the balancing length will be

A potentiometer arrangement is shows in Fig. 6.62 . The driver cell has emf e and internal resistance r . The resistance of potentiometer wire AB is R.F is the cell of emf e//3 and internal resistance r//3 . Balance point (J) can be obtained for all finite value of

Assertion: Potentiometer measures correct value of emf of a cell. Reason: No current flows through cell at null point of potentiometer.

A : When two cells of equal EMF and equal internal resistances are connected is parallel with positive plate of the other than , the net EMF , of the combination will be equal to the EMF of each cell. R : Effective internal resistance of the parallel combination of two identical cells will be half of the internal resistance of each cell.