A dipole of magnetic moment `vec(m)=(30 hati) (A) (m)^(2)` is placed along the y-axis in a, uniform magnetic field `vec(B)=(2 hat(i)+5 hat(j)) . (T)`. The torque acting on it is `(-alpha hat(k))`. Calculate `alpha`.

A dipole of magnetic moment vec(m)=30hatjA m^(2) is placed along the y-axis in a uniform magnetic field vec(B)= (2hat i +5hatj)T . The torque acting on it is

A magnet of magnetic moment 50 hat(i) A-m^(2) is placed along the x-axis in a magnetic field vec(B)=(0.5hat(i)+3.0hat(j))T . The torque acting on the magnet is

A magnet of magnetic moment 20_(hatk) Am^(2) is placed along the z- axis in a magnetic field vec(B)=(0.4hat(j)+0.5hat(k)) T . The torque acting on the magnet is

A "bar" magnet of moment bar(M)=hat(i)+hat(j) is placed in a magnetic field induction vec(B)=3hat(i)+4hat(j)+4hat(k) . The torque acting on the magnet is

A charged particle moving in a magnetic field vec(B) = hat(i) - hat(j) tesla, has an acceleration of 2 hat(i) + alpha hat(j) at some instant. Find the value of alpha

An alpha particle moving with the velocity vec v = u hat i + hat j ,in a uniform magnetic field vec B = B hat k . Magnetic force on alpha particle is

A charged particle with charge to mass ratio ((q)/(m)) = (10)^(3)/(19) Ckg^(-1) enters a uniform magnetic field vec(B) = 20 hat(i) + 30 hat(j) + 50 hat(k) T at time t = 0 with velocity vec(V) = (20 hat(i) + 50 hat(j) + 30 hat(k)) m//s . Assume that magnetic field exists in large space. During the further motion of the particle in the magnetic field, the angle between the magnetic field and velocity of the particle