A tangent galvanometer has a coil of 50 turns and `a` radius of 20 cm The horizontal component of the earth's magnetic field is `B_(H)=3 xx 10^(-5)T`. Find the current (in ampere) which gives a deflection of `45^(circ)`. (Take `pi=3` )

A tangent galvanometer has a coil of 50 turns and a radius of 20cm. The horizontal component of the earth's magnetic field is B_H = 3 xx 10^(-5) T . Find the current which gives a diflection of 45^) .

A tangent galvanometer has a coil of 25 turns and radius of 15 cm. The horizontal component of the earth's magnetic field is 3xx10^(-5)T . The current required to producea defection of 45^(@) in it, is

The coil of a tangent galvonometer of radius 12cm is having 200turns. If the forinzontal component of earth's magnetic field is 25muT . Find the current which gives a deflection of 60^(@) .

The horizontal component of the earth's magnetic field is 3.6 xx 10^(-5) T where the dip is 60^@ . Find the magnitude of the earth's magnetic field.

A tangent galvanometer has a cooil of 22 turns and mean radius 0.1 m. Find the reduction factor at a place , where B_(H)=0.3xx10^(-4)T .

A tangent galvanometer shown a deflection of 45^@ when 10 mA of current is passed through it. If the horizontal component of the earth's magnetic field is B_H = 3.6 xx 10^(-5) T and radius of the coil is 10cm , find the number of turns in the coil.

For a place, horizontal component of the earth's magnetic magnetic field is 3 xx 10^(-5) T . Calculate the magnetic field of the earth at this place when angle of dip is 45^@ N.

Tangent galvanometer is placed at a location where horizontal component of earth's magnetic field is B_H = 3.0 xx 10^(-5) T. Radius of the coil used in galvanometer is 25 cm and number of turns are 100. Find the current flowing through the galvanometer if deflection is 60^@