A common emitter amplifier is designed with `n-p-n` transistor `(alpha=0.99)`. The input resistance is `1K ohm` and load is `10 k ohm`. The voltage gain will be

A common-emitter amplifier is designed with an n-p-n transistor (alpha=0.99) .The input impedance is 1kOmega and the load is 10kOmega .The voltage gain will be

A common emitter amplifier is designed with NPN transistor (alpha = 0.99) . The input impedance is 1 K Omega and load is 10 K Omega . The voltage gain will be

A common emitter amplifier is designed with NPN transistor (alpha=0.99) . The input impedence is 1k Komega and load is 10 Komega . The voltage gain will be

A CE amplifier is designed with a transistor having alpha =0.99 . Input impedance is 1 k Omega and load is 10 k Omega . Voltage gain will be :

A non transistor operates as a common emitter amplifier, with a power gain of 60 dB. The input circuit resistance is 100 Omega and the output load resistance is 10 k Omega . The common emitter current gain beta is:

An npn transistor operates as a common emitter amplifier with a power gain of 10^6 . The input circuit resistance is 100 Omega and the output load resistance is 10 k Omega . The common emitter current gain ' beta ' will be (Round off to the Nearest Integer)

A common emitter circuit is used as an amplifier, its current gain is 50. if input resistance is 1kOmega and input voltage is 5 volt then output current will be

In a common emitter amplifier the load resistance of the output circuit is 792 times the resistance of the input circuit. If alpha = 0.99 . The voltage gain is.

The current gain in the CE mode of a transistor is 10. If the input impedance is 10 K Omega and load resistance = 60 K Omega , then the power gain will be