In a common emitter transistor, input current is `5 mu A` and `beta=100`. The circuit is operated with load resistance `10k ohm`. The voltage (in volt) acroșs the load resistance is

For a common - emitter transistor, input current is 5muA, beta = 100 circuit is operated at load resistance of 10 kOmega , then voltage across collector emiiter will be

In common emitter transistor, the input resistance is 200Omega and bad resistance is 40kOmega . If current gain is 80 then voltage gain is

A change of 0.2mA in the base current cause a change of 5mA in the collector current for a common emitter amplifier. (i) Find the a.c. current gain of the transistor (ii) If the input resistance is 2kOmega and its voltage gain is 75. Calculate the load resistance used in the circuit.

In a transistor, current gain is 100 . If the load resistance is 3 and the input resistance is 1k ohm , then what will be voltage gain?

A common emitter transistor amplifier has a current gain of 50 . If the load resistance is 4k Omega , and input resistance is 500 Omega , the voltage gain of amplifier is.

A common emitter amplifier has current gain 70. Its load resistance is 5 k Omega and input resistance is 500 Omega . The voltage gain is

A common emitter amplifier is designed with n-p-n transistor (alpha=0.99) . The input resistance is 1K ohm and load is 10 k ohm . The voltage gain will be

In a common emitter amplifier change in base current by 10 muA and collector current by 1mA if the input resistance of the transistor is 1 k omega and load resistacne of 6k omega is used in the circuit calculate (i) the current gain (ii) the voltage gain

In a common emitter amplifier , the input resistance is 1 Omega and load resistance is 10 K Omega . If the current gain is 100, the voltage gasin of the amplifier is