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If ab+bc+ca=0, then the value of ((b^(2)...

If `ab+bc+ca=0`, then the value of `((b^(2)-ca)(c^(2)-ab)+(a^(2)-bc)(c^(2)-ab)+(a^(2)-bc)(b^(2)-ca))/((a^(2)-bc)(b^(2)-ca)(c^(2)-ab))` is

A

A)`-1`

B

B)0

C

C)1

D

D)2

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