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A sum invested at 8% p.a. amounts to Rs....

A sum invested at 8% p.a. amounts to Rs.20280 at the end of one year, when the interest is compounded half yearly. What will be the simple interest on the same sum for `4(2)/(5)` years at double the earlier rate of interest ?

A

`Rs. 14500`

B

`Rs. 13200`

C

`Rs. 14200`

D

`Rs. 13800`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow these steps: ### Step 1: Understand the Problem We need to find the principal amount (P) that was invested at an interest rate of 8% per annum, compounded half-yearly, which amounts to Rs. 20,280 at the end of one year. After finding the principal, we will calculate the simple interest for a time period of \(4 \frac{2}{5}\) years at double the interest rate. ### Step 2: Calculate the Effective Rate and Time for Compounding Since the interest is compounded half-yearly, we need to adjust the rate and time: - The annual interest rate is 8%, so the half-yearly rate is: \[ \text{Half-yearly rate} = \frac{8\%}{2} = 4\% \] - The time for one year in half-yearly terms is: \[ \text{Time} = 1 \text{ year} = 2 \text{ half-years} \] ### Step 3: Use the Compound Interest Formula The formula for the amount (A) when compounded is: \[ A = P \left(1 + \frac{r}{100}\right)^n \] Where: - \(A\) = Amount after time \(n\) - \(P\) = Principal - \(r\) = Rate of interest - \(n\) = Number of compounding periods Substituting the known values: \[ 20280 = P \left(1 + \frac{4}{100}\right)^2 \] \[ 20280 = P \left(1.04\right)^2 \] \[ 20280 = P \times 1.0816 \] ### Step 4: Solve for Principal (P) Rearranging the equation to find \(P\): \[ P = \frac{20280}{1.0816} \] Calculating \(P\): \[ P = 18750 \] ### Step 5: Calculate the Simple Interest Now we need to calculate the simple interest for \(4 \frac{2}{5}\) years at double the earlier rate of interest. The new rate will be: \[ \text{New Rate} = 2 \times 8\% = 16\% \] Convert \(4 \frac{2}{5}\) years to an improper fraction: \[ 4 \frac{2}{5} = \frac{22}{5} \text{ years} \] Using the formula for Simple Interest (SI): \[ SI = \frac{P \times r \times t}{100} \] Substituting the values: \[ SI = \frac{18750 \times 16 \times \frac{22}{5}}{100} \] ### Step 6: Calculate Simple Interest Calculating the SI: \[ SI = \frac{18750 \times 16 \times 22}{500} \] \[ SI = \frac{6600000}{500} = 13200 \] ### Final Answer The simple interest on the same sum for \(4 \frac{2}{5}\) years at double the earlier rate of interest is Rs. 13,200. ---
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