To solve the problem step-by-step, we will follow the details provided in the question and the video transcript.
### Step 1: Determine the Purchase Price and Insured Amount
The man purchased the car for Rs 12 lakhs. He insured the car for 80% of its cost.
**Calculation:**
- Insured Amount = 80% of Purchase Price
- Insured Amount = 80% of 12,00,000 = 0.80 × 12,00,000 = Rs 9,60,000
**Hint:** To find the insured amount, multiply the purchase price by the percentage of insurance coverage.
### Step 2: Calculate Selling Price at Loss
The man sold the car at a 15% loss. We need to calculate the selling price (SP) after this loss.
**Calculation:**
- Loss = 15% of Purchase Price
- Loss = 15% of 12,00,000 = 0.15 × 12,00,000 = Rs 1,80,000
- Selling Price (SP) = Purchase Price - Loss
- SP = 12,00,000 - 1,80,000 = Rs 10,20,000
**Hint:** To find the selling price after a loss, subtract the loss amount from the original purchase price.
### Step 3: Calculate the Insurance Payout
After the accident, the insurance company paid 90% of the insured amount.
**Calculation:**
- Insurance Payout = 90% of Insured Amount
- Insurance Payout = 90% of 9,60,000 = 0.90 × 9,60,000 = Rs 8,64,000
**Hint:** To find the insurance payout, multiply the insured amount by the percentage the insurance company covers.
### Step 4: Calculate the Net Difference in Transactions
Now, we need to find the net difference between the selling price and the insurance payout.
**Calculation:**
- Net Difference = Selling Price - Insurance Payout
- Net Difference = 10,20,000 - 8,64,000 = Rs 1,56,000
**Hint:** To find the net difference, subtract the insurance payout from the selling price.
### Conclusion
The net difference in the two transactions is Rs 1,56,000, which can also be expressed as Rs 1.56 lakhs.
**Final Answer:** Rs 1.56 lakhs
