If `x=2+sqrt3` then find the valule of `x^4-8x^3+16x^2` is:

A

1

B

`-1`

C

2

D

0

Verified by Experts

The correct Answer is:

A

Similar Questions

Explore conceptually related problems

If x=2+sqrt(3) , then find the value of x^(4)-4x^(3)+x^(2)+x+1 .

If x=2+sqrt3 then the valule of x^3-x^-3 is: यदि x=2+sqrt3 है, तो x^3-x^-3 का मान ज्ञात करें |

If x=1/(2+sqrt3) ,find the value of x^(3)-x^(2)-11x+4

If x=2+sqrt5 then the valule of x^3-x^-3 is: यदि x=2+sqrt5 है, तो x^3-x^-3 का मान ज्ञात करें |

If sqrtx= sqrt3-sqrt5 , then the value of x^2-16x+6 is : यदि sqrtx= sqrt3-sqrt5 , x^2-16x+6 का मान ज्ञात करें :

If x=1+sqrt""2+sqrt""3 , then the value of 2x^(4)-8x^(3)-5x^(2)+26x-28 is :

If x=3+2i find the value of x^(4)-4x^(3)+4x^(2)+8x+39

If x=(sqrt(3)+1)/(2), find the value of 4x^(3)+2x^(2)-8x+7