If a sin theta+b cos theta=c, then a cos...

If a `sin theta+b cos theta=c`, then a `cos theta- b sin theta` is equal to

A

`sqrt(a^(2) + b^(2) + c^(2))`

B

`sqrt(a^(2) - b^(2) + c^(2))`

C

`sqrt(a^(2) + b^(2) -c^(2))`

D

`sqrt(a^(2) -b^(2) - c^(2))`

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The correct Answer is:

C

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