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If 4/(1+sqrt2+sqrt3)=a+b sqrt2+c sqrt3-d...

If `4/(1+sqrt2+sqrt3)=a+b sqrt2+c sqrt3-d sqrt6`, where a, b, c. d are natural numbers, then the value of a + b+ c + d is:

A

1

B

0

C

2

D

4

Text Solution

Verified by Experts

The correct Answer is:
D
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