Home
Class 14
MATHS
In the given figure, O is the centre of ...

In the given figure, O is the centre of the circle. If `angleBAO = 30^(@)` and `angleBCO = 50^(@)` , then `angleAOC` is equal to:

A

`60^(@)`

B

`80^(@)`

C

`40^(@)`

D

`160^(@)`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Similar Questions

Explore conceptually related problems

In the given figure, O is the centre of the circle. If angle BAO = 30^@ and angle BCO = 50^@ , then angle AOC is equal to: दिए गए आकृति में, O वृत्त का केंद्र है। यदि angle BAO = 30^@ और angle BCO = 50^@ , तो angle AOC का मान है :

In the given figure, O is the centre of the circle. angleAOB = 70^(@) , find angleOCD :

In figure, O is the centre of the circle angleBCO=30^(@) . Find X and Y.

In the given figure, O is the centre of circle. angleAOC = 120^(@) . Find angleBAC :

In the given figure, O is the centre of circle, angleAOB =100^(@) . Find angleBCD :

In the given figure, O is the centre of the circle angleAOB=90^@ Find m angleAPB