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The areas of three adjacent faces of a c...

The areas of three adjacent faces of a cuboid are `30 cm^(2), 20 cm^(2)` and `24 cm^(2)` . The volume of the cuboid is :

A

`200 cm^(3)`

B

`120 cm^(3)`

C

`180 cm^(3)`

D

`150 cm^(3)`

Text Solution

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The correct Answer is:
To find the volume of the cuboid given the areas of three adjacent faces, we can follow these steps: ### Step 1: Define the dimensions of the cuboid Let the dimensions of the cuboid be \( l \), \( b \), and \( h \). The areas of the three adjacent faces can be represented as: - Area of face 1: \( l \times b = 30 \, \text{cm}^2 \) - Area of face 2: \( b \times h = 20 \, \text{cm}^2 \) - Area of face 3: \( h \times l = 24 \, \text{cm}^2 \) ### Step 2: Set up the equations From the areas, we can set up the following equations: 1. \( lb = 30 \) (Equation 1) 2. \( bh = 20 \) (Equation 2) 3. \( hl = 24 \) (Equation 3) ### Step 3: Multiply all three equations To find the volume \( V \) of the cuboid, we can use the formula: \[ V = l \times b \times h \] We can find \( (lbh)^2 \) by multiplying all three equations: \[ (lb) \times (bh) \times (hl) = (lbh)^2 \] Substituting the values from the equations: \[ 30 \times 20 \times 24 = (lbh)^2 \] ### Step 4: Calculate the product Now, calculate the product: \[ 30 \times 20 = 600 \] \[ 600 \times 24 = 14400 \] So, we have: \[ (lbh)^2 = 14400 \] ### Step 5: Take the square root To find \( lbh \), we take the square root of both sides: \[ lbh = \sqrt{14400} \] Calculating the square root: \[ lbh = 120 \, \text{cm}^3 \] ### Conclusion The volume of the cuboid is \( 120 \, \text{cm}^3 \).
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