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Marked price of an article is Rs. 800 is...

Marked price of an article is Rs. 800 is sold at two equal successive discounts of x% equivalent to a single discount of Rs. 350 then what will be the value of x?

A

15

B

20

C

25

D

33.33

Text Solution

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The correct Answer is:
To find the value of \( x \) in the given problem, we can follow these steps: ### Step 1: Understand the Problem We have a marked price (MP) of an article which is Rs. 800. The article is sold at two equal successive discounts of \( x\% \). The total discount is equivalent to a single discount of Rs. 350. ### Step 2: Calculate the Selling Price (SP) The selling price (SP) after a total discount of Rs. 350 can be calculated as: \[ SP = MP - \text{Total Discount} \] Substituting the values: \[ SP = 800 - 350 = 450 \] ### Step 3: Set Up the Equation for Successive Discounts When two successive discounts of \( x\% \) are applied, the selling price can also be expressed as: \[ SP = MP \times (1 - \frac{x}{100}) \times (1 - \frac{x}{100}) \] This simplifies to: \[ SP = 800 \times \left(1 - \frac{x}{100}\right)^2 \] ### Step 4: Equate the Two Expressions for SP Now we can set the two expressions for SP equal to each other: \[ 450 = 800 \times \left(1 - \frac{x}{100}\right)^2 \] ### Step 5: Solve for \( x \) First, divide both sides by 800: \[ \frac{450}{800} = \left(1 - \frac{x}{100}\right)^2 \] This simplifies to: \[ \frac{9}{16} = \left(1 - \frac{x}{100}\right)^2 \] Next, take the square root of both sides: \[ \sqrt{\frac{9}{16}} = 1 - \frac{x}{100} \] This gives us: \[ \frac{3}{4} = 1 - \frac{x}{100} \] Now, rearranging the equation: \[ \frac{x}{100} = 1 - \frac{3}{4} = \frac{1}{4} \] Thus, multiplying both sides by 100: \[ x = 25 \] ### Conclusion The value of \( x \) is \( 25\% \).
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