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In DeltaABC measure of angle B is 90^@. ...

In `Delta`ABC measure of angle B is `90^@`. If sinA = 15/17, and AB = 0.8cm, then what is the length (in cm) of side AC?

A

1.7

B

1.5

C

2

D

2.5

Text Solution

AI Generated Solution

The correct Answer is:
To find the length of side AC in triangle ABC, where angle B is 90 degrees, we can follow these steps: ### Step 1: Understand the Triangle and Given Values We have a right triangle ABC with: - Angle B = 90 degrees - sin A = 15/17 - AB = 0.8 cm ### Step 2: Use the Definition of Sine The sine of angle A in a right triangle is defined as the ratio of the length of the opposite side (BC) to the length of the hypotenuse (AC). Thus, we can write: \[ \sin A = \frac{\text{Opposite}}{\text{Hypotenuse}} = \frac{BC}{AC} \] Given that \(\sin A = \frac{15}{17}\), we can set: - BC = 15k (where k is a scaling factor) - AC = 17k ### Step 3: Use the Pythagorean Theorem According to the Pythagorean theorem: \[ AB^2 + BC^2 = AC^2 \] Substituting the known values: \[ (0.8)^2 + (15k)^2 = (17k)^2 \] Calculating \(0.8^2\): \[ 0.64 + 225k^2 = 289k^2 \] ### Step 4: Rearranging the Equation Now, rearranging the equation: \[ 289k^2 - 225k^2 = 0.64 \] \[ 64k^2 = 0.64 \] Dividing both sides by 64: \[ k^2 = \frac{0.64}{64} = 0.01 \] Taking the square root: \[ k = 0.1 \] ### Step 5: Find the Length of AC Now, substituting the value of k back into the expression for AC: \[ AC = 17k = 17 \times 0.1 = 1.7 \text{ cm} \] ### Conclusion The length of side AC is **1.7 cm**. ---
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