Train A' runs at a speed of 80 kmph and leaves station X' at 11.00 a.m. Train 'B' leaves station 'X at 11.15 a.m. in the same direction, on the same day . At what speed train 'B' should run in order to catch train 'A at station 'Y located at a distance of 60 km?

Options

A. 110 km/h
B. 115 km/h
C. 125 km/h
D. 120 km/h

Answer

To solve the problem, we need to determine the speed at which Train B must travel in order to catch up with Train A before they reach Station Y, which is 60 km away from Station X.

### Step-by-Step Solution:

1. **Calculate the time taken by Train A to reach Station Y:**
- Train A leaves at 11:00 a.m. and travels at a speed of 80 km/h.
- The distance to Station Y is 60 km.
- Time = Distance / Speed
- Time taken by Train A = 60 km / 80 km/h = 0.75 hours (or 45 minutes).

2. **Determine the time Train A leaves Station Y:**
- Since Train A leaves at 11:00 a.m. and takes 45 minutes to reach Station Y, it will arrive at Station Y at:
- 11:00 a.m. + 0.75 hours = 11:45 a.m.

3. **Calculate the time when Train B leaves Station X:**
- Train B leaves at 11:15 a.m.

4. **Determine the time Train B has to reach Station Y:**
- Train B has from 11:15 a.m. to 11:45 a.m. to reach Station Y.
- This gives Train B a total of 30 minutes (or 0.5 hours) to reach Station Y.

5. **Calculate the speed required for Train B:**
- To catch Train A at Station Y, Train B must cover the same distance (60 km) in the time available (0.5 hours).
- Speed = Distance / Time
- Speed required for Train B = 60 km / 0.5 hours = 120 km/h.

### Final Answer:
Train B should run at a speed of **120 km/h** to catch Train A at Station Y.

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