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Delta PQR is right angled at Q. If angl...

`Delta PQR` is right angled at Q. If ` angle R = 30^(@),` then find the value of (cos P -1/3).

A

`1//6`

B

`(2 sqrt2 -1) sqrt2`

C

`-1 //sqrt3`

D

`(sqrt3 -4 ) //2 sqrt3`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will analyze the triangle PQR, which is right-angled at Q and has angle R equal to 30 degrees. We need to find the value of (cos P - 1/3). ### Step 1: Identify the angles in triangle PQR Since triangle PQR is right-angled at Q, we know: - Angle Q = 90 degrees - Angle R = 30 degrees Using the property that the sum of angles in a triangle equals 180 degrees, we can find angle P. ### Step 2: Calculate angle P Using the angle sum property: \[ \text{Angle P} + \text{Angle Q} + \text{Angle R} = 180^\circ \] Substituting the known values: \[ \text{Angle P} + 90^\circ + 30^\circ = 180^\circ \] \[ \text{Angle P} + 120^\circ = 180^\circ \] \[ \text{Angle P} = 180^\circ - 120^\circ = 60^\circ \] ### Step 3: Calculate cos P Now that we have angle P, we can find cos P: \[ \text{cos P} = \text{cos}(60^\circ) \] From trigonometric values, we know: \[ \text{cos}(60^\circ) = \frac{1}{2} \] ### Step 4: Substitute into the expression (cos P - 1/3) Now we substitute cos P into the expression: \[ \text{cos P} - \frac{1}{3} = \frac{1}{2} - \frac{1}{3} \] ### Step 5: Find a common denominator and simplify To subtract these fractions, we need a common denominator. The least common multiple of 2 and 3 is 6. \[ \frac{1}{2} = \frac{3}{6} \quad \text{and} \quad \frac{1}{3} = \frac{2}{6} \] Now we can perform the subtraction: \[ \frac{3}{6} - \frac{2}{6} = \frac{1}{6} \] ### Final Answer Thus, the value of (cos P - 1/3) is: \[ \frac{1}{6} \] ---
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