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If x and y are positive integer numbers ...

If x and y are positive integer numbers and `(3x)/(y)=6` then find the minimum value of `3x-4y`.

A

2

B

1

C

6

D

8

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the minimum value of \(3x - 4y\) given the equation \(\frac{3x}{y} = 6\) where \(x\) and \(y\) are positive integers. ### Step-by-Step Solution: 1. **Start with the given equation:** \[ \frac{3x}{y} = 6 \] This can be rewritten as: \[ 3x = 6y \] Dividing both sides by 3 gives: \[ x = 2y \] 2. **Substitute \(x\) in the expression \(3x - 4y\):** We need to find the minimum value of: \[ 3x - 4y \] Substituting \(x = 2y\) into the expression: \[ 3(2y) - 4y = 6y - 4y = 2y \] 3. **Minimize \(2y\):** Since \(y\) is a positive integer, the smallest value \(y\) can take is 1. Therefore: \[ 2y = 2 \times 1 = 2 \] 4. **Conclusion:** The minimum value of \(3x - 4y\) is: \[ \boxed{2} \]
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