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If 5 sin theta = 3, the numerical value ...

If `5 sin theta = 3,` the numerical value of`(sec theta - tan theta)/(sec theta + tan theta)` is
यदि `5 sin theta= 3,` समीकरण का संख्यात्मक मान है `(sec theta - tan theta)/(sec theta + tan theta)`

A

`(1)/(2)`

B

`(1)/(4)`

C

`(1)/(3)`

D

`(1)/(5)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the numerical value of \((\sec \theta - \tan \theta)/(\sec \theta + \tan \theta)\) given that \(5 \sin \theta = 3\). ### Step-by-step Solution: 1. **Find \(\sin \theta\)**: \[ \sin \theta = \frac{3}{5} \] 2. **Construct a right triangle**: - In a right triangle, let the opposite side (perpendicular) be \(3k\) and the hypotenuse be \(5k\). Here, \(k\) is a scaling factor. - To find the adjacent side (base), we use the Pythagorean theorem: \[ \text{Base} = \sqrt{(\text{Hypotenuse})^2 - (\text{Opposite})^2} = \sqrt{(5k)^2 - (3k)^2} = \sqrt{25k^2 - 9k^2} = \sqrt{16k^2} = 4k \] 3. **Calculate \(\sec \theta\) and \(\tan \theta\)**: - \(\sec \theta = \frac{\text{Hypotenuse}}{\text{Base}} = \frac{5k}{4k} = \frac{5}{4}\) - \(\tan \theta = \frac{\text{Opposite}}{\text{Base}} = \frac{3k}{4k} = \frac{3}{4}\) 4. **Substitute \(\sec \theta\) and \(\tan \theta\) into the expression**: \[ \frac{\sec \theta - \tan \theta}{\sec \theta + \tan \theta} = \frac{\frac{5}{4} - \frac{3}{4}}{\frac{5}{4} + \frac{3}{4}} \] 5. **Simplify the expression**: - The numerator: \[ \frac{5}{4} - \frac{3}{4} = \frac{2}{4} = \frac{1}{2} \] - The denominator: \[ \frac{5}{4} + \frac{3}{4} = \frac{8}{4} = 2 \] 6. **Final calculation**: \[ \frac{\frac{1}{2}}{2} = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4} \] Thus, the numerical value of \((\sec \theta - \tan \theta)/(\sec \theta + \tan \theta)\) is \(\frac{1}{4}\).

To solve the problem, we need to find the numerical value of \((\sec \theta - \tan \theta)/(\sec \theta + \tan \theta)\) given that \(5 \sin \theta = 3\). ### Step-by-step Solution: 1. **Find \(\sin \theta\)**: \[ \sin \theta = \frac{3}{5} \] ...
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