If `1 xx 3 xx 5 = 19 25 and 7 xx 9 xx 11 = 4981121,`then find the valae of `19 xx 21 xx 23 =` ?
यदि `1 xx 3 xx 5 = 1925` और `7 xx 9 xx 11 = 4981121` हो, तो `19 xx 21 xx 23` किसके बराबर होगा?

Options

A. A)361529441
B. B)361441289
C. C)441361289
D. D)361441529

Explanation

To solve the problem, we need to identify the pattern used in the given expressions.

1. **Understanding the first expression**:
We are given that \(1 \times 3 \times 5 = 1925\).
- Here, we can see that the numbers are not multiplied in the traditional sense. Instead, we can observe that:
- \(1^2 = 1\)
- \(3^2 = 9\)
- \(5^2 = 25\)
- When we concatenate these squares, we get \(1925\) (i.e., \(1\) followed by \(9\) followed by \(25\)).

2. **Understanding the second expression**:
Next, we have \(7 \times 9 \times 11 = 4981121\).
- Again, we can look at the squares:
- \(7^2 = 49\)
- \(9^2 = 81\)
- \(11^2 = 121\)
- Concatenating these gives us \(4981121\) (i.e., \(49\) followed by \(81\) followed by \(121\)).

3. **Finding the value of \(19 \times 21 \times 23\)**:
Now, we need to apply the same pattern to \(19 \times 21 \times 23\).
- Calculate the squares:
- \(19^2 = 361\)
- \(21^2 = 441\)
- \(23^2 = 529\)
- Concatenating these squares gives us \(361441529\).

Thus, the value of \(19 \times 21 \times 23\) is **361441529**.