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If the sum of two angles is 135° and the...

If the sum of two angles is 135° and their difference is `pi`/12 , then the circular measure of the greater angle is.
यदि दो कोणों का योगफल 135° है और उनका अंतर `pi`/12 है, तो बड़े कोण का वृत्तीय माप है:

A

A)`(2pi)/3`

B

B)`(3pi)/5`

C

C)`(5pi)/12`

D

D)`(pi)/3`

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To solve the problem, we need to find the circular measure of the greater angle given that the sum of two angles is 135° and their difference is π/12. ### Step-by-Step Solution: 1. **Set Up Equations**: Let the two angles be \( A \) and \( B \). We know: \[ A + B = 135^\circ \quad \text{(1)} \] \[ A - B = \frac{\pi}{12} \quad \text{(2)} \] 2. **Convert π/12 to Degrees**: Since \( \pi \) radians is equivalent to \( 180^\circ \), we can convert \( \frac{\pi}{12} \) to degrees: \[ \frac{\pi}{12} = \frac{180^\circ}{12} = 15^\circ \] Thus, equation (2) becomes: \[ A - B = 15^\circ \quad \text{(3)} \] 3. **Add Equations (1) and (3)**: To find \( A \), we can add equations (1) and (3): \[ (A + B) + (A - B) = 135^\circ + 15^\circ \] This simplifies to: \[ 2A = 150^\circ \] Therefore: \[ A = \frac{150^\circ}{2} = 75^\circ \] 4. **Substitute to Find B**: Now we can substitute \( A \) back into equation (1) to find \( B \): \[ 75^\circ + B = 135^\circ \] Solving for \( B \): \[ B = 135^\circ - 75^\circ = 60^\circ \] 5. **Identify the Greater Angle**: The greater angle is \( A = 75^\circ \). 6. **Convert to Circular Measure**: To find the circular measure of the greater angle, we convert \( 75^\circ \) to radians: \[ \text{Circular Measure} = A \times \frac{\pi}{180^\circ} = 75^\circ \times \frac{\pi}{180^\circ} \] Simplifying this: \[ = \frac{75\pi}{180} = \frac{5\pi}{12} \] ### Final Answer: The circular measure of the greater angle is \( \frac{5\pi}{12} \). ---

To solve the problem, we need to find the circular measure of the greater angle given that the sum of two angles is 135° and their difference is π/12. ### Step-by-Step Solution: 1. **Set Up Equations**: Let the two angles be \( A \) and \( B \). We know: \[ ...
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