If A denotes - C denotes `xx` D denotes `:-` E denotes + then 14C3A12E4D2=?
यदि A- को प्रदर्शित करता है C,`xx` को प्रदर्शित करता है D `:-` को प्रदर्शित करता है E + को प्रदर्शित करता है तो 14C3A12E4D2=?

Options

A. A. 6
B. B. 17
C. C. 28
D. D. 32

Explanation

To solve the expression \( 14C3A12E4D2 \) using the given notations, we will follow these steps:

1. **Identify the operations based on the given notations**:
- \( A \) denotes subtraction (-)
- \( C \) denotes multiplication (×)
- \( D \) denotes division (÷)
- \( E \) denotes addition (+)

2. **Rewrite the expression using the identified operations**:
- The expression \( 14C3A12E4D2 \) can be rewritten as:
\[ 14 \times 3 - 12 + 4 \div 2 \]

3. **Follow the order of operations (BODMAS/BIDMAS)**:
- According to the order of operations, we first perform division, then multiplication, followed by addition and subtraction.

4. **Calculate the division first**:
- Calculate \( 4 \div 2 \):
\[ 4 \div 2 = 2 \]
- Now, substitute this back into the expression:
\[ 14 \times 3 - 12 + 2 \]

5. **Next, perform the multiplication**:
- Calculate \( 14 \times 3 \):
\[ 14 \times 3 = 42 \]
- Substitute this back into the expression:
\[ 42 - 12 + 2 \]

6. **Now, perform the subtraction**:
- Calculate \( 42 - 12 \):
\[ 42 - 12 = 30 \]
- Substitute this back into the expression:
\[ 30 + 2 \]

7. **Finally, perform the addition**:
- Calculate \( 30 + 2 \):
\[ 30 + 2 = 32 \]

Thus, the final answer is:
\[ \boxed{32} \]