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A, B and C can do a piece of work in 20,...

A, B and C can do a piece of work in 20, 40 and 80 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?

A

7 days

B

15 days

C

18 days

D

16 days

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine how many days A can complete the work if he is assisted by B and C on every third day. Let's break it down step by step. ### Step 1: Determine the work rates of A, B, and C - A can complete the work in 20 days, so his work rate is: \[ \text{Work rate of A} = \frac{1}{20} \text{ (work per day)} \] - B can complete the work in 40 days, so his work rate is: \[ \text{Work rate of B} = \frac{1}{40} \text{ (work per day)} \] - C can complete the work in 80 days, so his work rate is: \[ \text{Work rate of C} = \frac{1}{80} \text{ (work per day)} \] ### Step 2: Calculate the combined work rate of A, B, and C On the third day, A is assisted by B and C. Therefore, the combined work rate of A, B, and C is: \[ \text{Combined work rate} = \text{Work rate of A} + \text{Work rate of B} + \text{Work rate of C} \] Calculating this: \[ \text{Combined work rate} = \frac{1}{20} + \frac{1}{40} + \frac{1}{80} \] To add these fractions, we need a common denominator. The least common multiple of 20, 40, and 80 is 80: \[ \text{Combined work rate} = \frac{4}{80} + \frac{2}{80} + \frac{1}{80} = \frac{7}{80} \] ### Step 3: Calculate the work done in a cycle of 3 days In the first two days, only A works: \[ \text{Work done by A in 2 days} = 2 \times \frac{1}{20} = \frac{2}{20} = \frac{1}{10} \] On the third day, A, B, and C work together: \[ \text{Work done by A, B, and C on the 3rd day} = \frac{7}{80} \] Thus, the total work done in 3 days is: \[ \text{Total work in 3 days} = \frac{1}{10} + \frac{7}{80} \] Converting \(\frac{1}{10}\) to a fraction with a denominator of 80: \[ \frac{1}{10} = \frac{8}{80} \] So, \[ \text{Total work in 3 days} = \frac{8}{80} + \frac{7}{80} = \frac{15}{80} = \frac{3}{16} \] ### Step 4: Determine how many cycles are needed to complete the work To complete 1 unit of work, we can find out how many cycles of 3 days are needed: \[ \text{Number of cycles} = \frac{1}{\frac{3}{16}} = \frac{16}{3} \approx 5.33 \text{ cycles} \] This means it takes 5 complete cycles (15 days) and a portion of the next cycle. ### Step 5: Calculate the work done in 15 days In 15 days, the total work done is: \[ \text{Total work done in 15 days} = 5 \times \frac{3}{16} = \frac{15}{16} \] ### Step 6: Determine the remaining work The remaining work after 15 days is: \[ \text{Remaining work} = 1 - \frac{15}{16} = \frac{1}{16} \] ### Step 7: Calculate the work done on the 16th and 17th days On the 16th and 17th days, A works alone: - Work done by A in 2 days: \[ \text{Work done by A in 2 days} = 2 \times \frac{1}{20} = \frac{2}{20} = \frac{1}{10} \] Now, we need to check if the remaining work can be completed in these 2 days: - Convert \(\frac{1}{10}\) to a fraction with a denominator of 16: \[ \frac{1}{10} = \frac{1.6}{16} \] Since \(\frac{1.6}{16} > \frac{1}{16}\), A can complete the remaining work on the 17th day. ### Conclusion Thus, the total time taken to complete the work is: \[ 15 \text{ days} + 1 \text{ day} = 16 \text{ days} \] ### Final Answer **A can complete the work in 16 days.** ---
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