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The ratio between 2 numbers is 4:5 and t...

The ratio between 2 numbers is 4:5 and the sum of their squares is 1025 , then the numbers are

A

20 and 25

B

24 and 30

C

8 and 10

D

40 and 50

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow the given conditions: the ratio of two numbers is 4:5, and the sum of their squares is 1025. ### Step 1: Define the Variables Let the two numbers be \( x \) and \( y \). According to the ratio provided: \[ \frac{x}{y} = \frac{4}{5} \] ### Step 2: Express One Variable in Terms of the Other From the ratio, we can express \( x \) in terms of \( y \): \[ x = \frac{4}{5}y \] ### Step 3: Set Up the Equation for the Sum of Squares We are given that the sum of their squares is 1025: \[ x^2 + y^2 = 1025 \] ### Step 4: Substitute the Expression for \( x \) Substituting \( x = \frac{4}{5}y \) into the equation: \[ \left(\frac{4}{5}y\right)^2 + y^2 = 1025 \] ### Step 5: Simplify the Equation Calculating \( \left(\frac{4}{5}y\right)^2 \): \[ \frac{16}{25}y^2 + y^2 = 1025 \] Now, convert \( y^2 \) into a fraction with a common denominator: \[ \frac{16}{25}y^2 + \frac{25}{25}y^2 = 1025 \] Combine the fractions: \[ \frac{41}{25}y^2 = 1025 \] ### Step 6: Solve for \( y^2 \) Multiply both sides by 25 to eliminate the fraction: \[ 41y^2 = 1025 \times 25 \] Calculating \( 1025 \times 25 \): \[ 41y^2 = 25625 \] Now, divide both sides by 41: \[ y^2 = \frac{25625}{41} \] Calculating this gives: \[ y^2 = 625 \] ### Step 7: Find \( y \) Taking the square root of both sides: \[ y = \sqrt{625} = 25 \] ### Step 8: Find \( x \) Now substitute \( y \) back into the equation for \( x \): \[ x = \frac{4}{5} \times 25 = 20 \] ### Conclusion Thus, the two numbers are: \[ \text{The numbers are } 20 \text{ and } 25. \]
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