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The third propotional to 9 and 15 is:...

The third propotional to 9 and 15 is:

A

18

B

36

C

27

D

25

Text Solution

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The correct Answer is:
To find the third proportional to 9 and 15, we can follow these steps: ### Step 1: Understand the concept of third proportional The third proportional to two numbers \( a \) and \( b \) is a number \( x \) such that the ratio \( a:b \) is equal to the ratio \( b:x \). ### Step 2: Set up the proportion Let the third proportional be \( x \). We can express the relationship as: \[ \frac{9}{15} = \frac{15}{x} \] ### Step 3: Cross-multiply to solve for \( x \) Cross-multiplying gives us: \[ 9 \cdot x = 15 \cdot 15 \] ### Step 4: Simplify the equation Calculating the right side: \[ 15 \cdot 15 = 225 \] So we have: \[ 9x = 225 \] ### Step 5: Solve for \( x \) Now, divide both sides by 9: \[ x = \frac{225}{9} \] ### Step 6: Perform the division Calculating \( \frac{225}{9} \): \[ 225 \div 9 = 25 \] ### Conclusion Thus, the third proportional to 9 and 15 is: \[ \boxed{25} \] ---
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Knowledge Check

  • The third proportional to 9 and 12 is

    A
    10.5
    B
    8
    C
    16
    D
    21
  • Statement I: As radius of soap bubble increases, the insude pressure increases. Statement II: Excess pressure in soap bubble is inversely propotional to radius.

    A
    Both statement 1 and statemet 2 are true and statement 2 is the correct explanation of statement 1.
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    Both statement 1 and statement 2 are true but statement 2 is not the correct explanantion of statement 7
    C
    Statement 1 is true but statement 2 is false.
    D
    Statement 1 is false but statement 2 is false.
  • Conductivity (unit siemens) is directly propotional to area of the vessel and the concentration of the solution it and is inversely proportional to the length of the vessel then the unit of constant of proportionality is

    A
    `"Sm mol"^(-1)`
    B
    `Sm^(2) mol^(-1)`
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