Home
Class 14
MATHS
The compound interest on a sum for 5^(th...

The compound interest on a sum for `5^(th)` year is ₹ 7800 and compound interest for sixth year is ₹ 9048 (interest is compounded annually). What is the rate of interest?

A

`12%`

B

`15%`

C

`16%`

D

`14%`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the rate of interest based on the given compound interest for the 5th and 6th years, we can follow these steps: ### Step 1: Understand the relationship between the compound interest for the 5th and 6th years. The compound interest for the 5th year is given as ₹ 7800, and for the 6th year, it is ₹ 9048. The difference between the interest for these two years will help us find the rate of interest. ### Step 2: Calculate the difference in compound interest. The difference in compound interest between the 6th year and the 5th year is: \[ \text{Difference} = \text{CI for 6th year} - \text{CI for 5th year} = 9048 - 7800 = 1248 \] ### Step 3: Relate the difference to the principal and rate of interest. The difference in compound interest between two consecutive years is equal to the principal amount at the beginning of the 6th year multiplied by the rate of interest (expressed as a decimal). Therefore, we can express this as: \[ \text{Difference} = P \times \frac{R}{100} \] Where \( P \) is the principal amount at the beginning of the 6th year, and \( R \) is the rate of interest. ### Step 4: Find the principal amount at the beginning of the 6th year. The amount at the end of the 5th year is the principal for the 6th year. The amount at the end of the 5th year can be calculated as: \[ \text{Amount at the end of 5th year} = \text{CI for 5th year} + \text{Principal} \] Let’s denote the principal as \( P \). The amount at the end of the 5th year is: \[ A_5 = P + 7800 \] At the end of the 6th year, the amount is: \[ A_6 = A_5 + 9048 = (P + 7800) + 9048 \] Thus, the principal at the beginning of the 6th year is: \[ P + 7800 \] ### Step 5: Set up the equation. Substituting the principal into the difference equation, we have: \[ 1248 = (P + 7800) \times \frac{R}{100} \] ### Step 6: Solve for the rate of interest. We can express \( P + 7800 \) in terms of the amount at the end of the 5th year: \[ P + 7800 = A_5 \] Now, we need to express \( A_5 \) in terms of \( R \): \[ A_5 = 7800 + P \] Substituting this back into the equation gives us: \[ 1248 = (A_5) \times \frac{R}{100} \] To find \( R \), we can rearrange this equation: \[ R = \frac{1248 \times 100}{A_5} \] ### Step 7: Calculate the value of \( R \). Since we know \( A_5 \) is equal to \( P + 7800 \), we can assume \( P \) is the principal amount that we need to find. However, we can also find \( R \) directly from the difference in interest: \[ R = \frac{1248 \times 100}{7800} \] Calculating this gives: \[ R = \frac{124800}{7800} = 16 \] ### Conclusion: The rate of interest is \( R = 16\% \).
Promotional Banner

Similar Questions

Explore conceptually related problems

The compound interest on a sum for 4^(th) year is Rs 6000 and compound interest for 5^(th) year is Rs 6750(interest is compounded annually). What is the rate of interest?

A certain sum becomes 16 times in 4 years at compound interest, compounded annually. What is the rate of interest?

The compound interest on a sum for 2 years is Rs. 832 and the simple interest on the same sum at the same rate for the same period is Rs. 800. What is the rate of interest?

A sum of Rs. 10500 becomes Rs. 17745 in 2 years at the rate of compound interest. If the interest is compounded annually then what will be the rate of interest?

Asum of Rs 11700 becomes Rs 16848 in 2 years at the rate of compoundinterest. If the interest is compounded annually, then what will be the rate of interest?

A sum of ₹4500 is lent at compound interest. If the rate of interest is 10% per annum (interest is compounded annually), then what will be the amount after 3 years?