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In finding the HCF of two numbers by div...

In finding the HCF of two numbers by division method, the last divisor is 174 and the quotient are 1, 7 and 2, respectively. If the sum of the two numbers is divided by 11. the remainder is:

A

2

B

8

C

1

D

7

Text Solution

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The correct Answer is:
To find the remainder when the sum of two numbers is divided by 11, we can follow these steps: ### Step 1: Identify the last divisor and the quotients The last divisor is given as 174. The quotients are 1, 7, and 2. ### Step 2: Calculate the second last dividend Using the last divisor and the last quotient: - Second last dividend = Last divisor × Last quotient - Second last dividend = 174 × 2 = 348 ### Step 3: Calculate the first dividend Now, using the second last dividend and the second last quotient: - First dividend = Second last dividend × Second last quotient + Last divisor - First dividend = 348 × 7 + 174 - First dividend = 2436 + 174 = 2610 ### Step 4: Calculate the first number Now, we have the first dividend as 2610. ### Step 5: Calculate the sum of the two numbers Now, we can find the sum of the two numbers: - Sum of the two numbers = First dividend + Second last dividend - Sum of the two numbers = 2610 + 348 = 2958 ### Step 6: Calculate the sum of the two numbers Now, we can find the sum of the two numbers: - Sum of the two numbers = 2610 + 2958 = 5568 ### Step 7: Find the remainder when the sum is divided by 11 Now, we need to divide the sum (5568) by 11 and find the remainder: - 5568 ÷ 11 = 506 remainder 2 ### Conclusion The remainder when the sum of the two numbers is divided by 11 is **2**. ---
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