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A mixture of 30 litres of spirit and wat...

A mixture of 30 litres of spirit and water contains 20% of water in it. How much water must be added to it, to make the water 25% in the new mixture ?

A

3 litres

B

2 litres

C

4 litres

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we can follow these instructions: ### Step 1: Determine the amount of water in the initial mixture. The mixture is 30 liters and contains 20% water. \[ \text{Amount of water} = 20\% \text{ of } 30 \text{ liters} = \frac{20}{100} \times 30 = 6 \text{ liters} \] ### Step 2: Determine the amount of spirit in the initial mixture. Since the total mixture is 30 liters and we have found that there are 6 liters of water, we can find the amount of spirit. \[ \text{Amount of spirit} = 30 \text{ liters} - \text{Amount of water} = 30 - 6 = 24 \text{ liters} \] ### Step 3: Set up the equation for the new mixture. Let \( x \) be the amount of water to be added. After adding \( x \) liters of water, the new total volume of the mixture will be \( 30 + x \) liters. The total amount of water will then be \( 6 + x \) liters. We want the new mixture to have 25% water. Therefore, we can set up the equation: \[ \frac{6 + x}{30 + x} = \frac{25}{100} \] ### Step 4: Cross-multiply to eliminate the fraction. Cross-multiplying gives us: \[ 100(6 + x) = 25(30 + x) \] ### Step 5: Simplify the equation. Expanding both sides: \[ 600 + 100x = 750 + 25x \] ### Step 6: Rearrange the equation to isolate \( x \). Bringing all terms involving \( x \) to one side and constant terms to the other side: \[ 100x - 25x = 750 - 600 \] This simplifies to: \[ 75x = 150 \] ### Step 7: Solve for \( x \). Dividing both sides by 75: \[ x = \frac{150}{75} = 2 \] ### Conclusion: Thus, the amount of water that must be added to the mixture to make the water 25% in the new mixture is **2 liters**. ---
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