Line `(x-2)/alpha=(y-2)/(-3)=(z+2)/2` lies in `x+3y-2z+beta=0` then `alpha+beta=`?

Let the line (x-2)/3=(y-1)/-5=(z+2)/2 lie in the plane x+3y-alpha z+beta=0 then (alpha, beta) equals (A) (6,-17) (B) (-6,7) (C) (5,-15) (D) (-5,15)

Suppose the line (x-2)/(alpha) = (y-2)/(-5) = (z+2)/(2) lies on the plane x + 3y - 2z + beta = 0 . Then (alpha + beta) is equal to ________.

Let the line (x-2)/(3)=(y-1)/(-5)=(z+2)/(2) lie in the plane x+3y-alpha z+ beta=0 then the value of alpha+beta=

Let the line (x-2)/(3)=(y-1)/(-5)=(z+2)/(2) lies in the plane x+3y-alphaz+beta=0 . Then, (alpha, beta) equals

If the line (x-2)/3 =(y-1)/-5 =(z+2)/2 lies in the plane x+3y - alphaz + beta=0 , then: (alpha, beta)-=

Let the line (x-2)/(3)=(y-1)/(-5)=(z+2)/(2) lies in the plane x+3y-alpha z +beta=0 . Then, (alpha,beta) equals

If the line (x-2)/(3)=(y+1)/(5)=(z-2)/(2) lies in the plane alpha x+2y+z-beta=0 then (alpha, beta) equals

Let the line (x-2)/3 = (y-1)/-5 =(z+2)/2 lie in the plane x+3y - alphaz + beta=0 . Then, (alpha,beta) equals