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When H(2)S is passed through Hg(2)^(2+),...

When `H_(2)S` is passed through `Hg_(2)^(2+)`, we get :

A

`HgS`

B

`HgS + Hg_(2)S`

C

`HgS + Hg`

D

`Hg_(2)S`

Text Solution

Verified by Experts

The correct Answer is:
C
`Hg_(2)Cl_(2) + H_(2)S rarr 2HCl + underset((ppt))(HgS) + Hg`
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