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KCl crystallizes in the same type of ...

KCl crystallizes in the same type of lattice as done NaCl . Given that `r_(Na^(+))//r_(Cl^(-)) = 0.50` and `r_(Na^(+))//r_(K^(+)) = 0.70` , Calculate the ratio of the side of the unit cell for KCl to that for NaCl:

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`(r_(Na^(+)))/(r_(Cl^(-)))=0.55, (r_(Na^(+)))/(r_(Cl^(-)))+1=1.55`
`(r_(K^(+)))/(r_(Cl^(-)))=0.74, (r_(K^(+)))/(r_(Cl^(-)))+1=1.74`
Dividing (ii) by (i), `(r_(K^(+))+r_(Cl^(-)))/(r_(Na^(+))+r_(Cl^(-)))=(1.74)/(1.55)=1.122`
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