Home
Class 12
CHEMISTRY
The ionic radii of Rb^(+) and Br^(-) ion...

The ionic radii of `Rb^(+)` and `Br^(-)` ions are 147 pm and and 195 pm resectively. Deduce the possible C.N of `Rb^(+)` ions in RbBr

Text Solution

Verified by Experts

The correct Answer is:
8
Radius ratio `(r^(+)//r^(-))=(("147pm"))/(("195pm"))=0.753`
`therefore` The possible C.N. of `Rb^(+)` ion in RbBr = 8.
Promotional Banner

Similar Questions

Explore conceptually related problems

NaCl crystal possesses a crystal structure having face-centred cubic unit cell. If the radii of Na^(+)andCl^(-) ions are 95 and 181 pm, respectively, then the edge length of its unit cell is-

The two ions A^(+)andB^(-) have radii 102 and 200 pm respectively. Predict the coordination number of A^(+) and crystal structure of compound AB.

(i) What is ferromagnetic substance? (ii) KBr crystallises in face-centred cubic (fcc) crystals. The density and formula mass of KBr crystal are 2.65g*cm^(-3) and 119g*mol^(-1) respectively. Find the distance between K^(+)andBr^(-) ions in KBr crystal. or, (i) Which kind of defect in ionic crystal does not alter the density? (ii) An element X has atomic mass 60g*mol^(-1) and density 6.23g*cm^(-3) . The edge length of its unit cell is 400 pm. Identify the type of the unit cubic cell. Calculate the radius of X atom.

A unit call of NaCl has four formula units. In NaCl crystal, radius ratio (r_(+)//r_(-)) is 0.69 and edge-length of the unit cell is twice the sum of the radii of Na^(+)andCl^(-) ions. If the radius of Na^(+) is 116 pm then find the density of NaCl crystal. Formula mass of NaCl = 58.5g*mol^(-1) .

The unit cell edge length of NaF crystal is 4.634Å . If the ionic radius of Na^(+) ion is 95 pm, what is the ionic radius of F^(-) ion, assuming that anion-anion contact and face centred cubic lattice?

H, He^(+), Li^(2+) are examples of atoms or ions with one electron each . The energy of such atoms when in the n-th energy state (according to Bohr,s theory , n=1,2,3…. =principal quantum number ) is E_n =(-13.6 Z^2)/(n^2) eV (1 eV =1.6xx10^(-19)J) . For the ground state ,n=1 . in order to raise the atom from the ground state to n=f , the suitable incident light should have a wavelength given by lambda=(hc)/(E_f-E_1) . But the atom cannot stay permanently in the f-energy state, ultimately , it comes to the ground state by radiating the extra energy , E_f-E_1 as electromagnetic radiation . The electron of the atom comes from n=f to n=1 in one or more steps using the permitted energy levels . As a result there is a possibility of emission of radiation with more than one wavelength from the atom. Planck's constant =6.63 xx10^(-34)J*s and velocity of light c=3xx10^(8)m*s^(-1) . The wavelength of radiation emitted for the transition of the electron of He^+ ion from n=4 to n=2 is

H, He^(+), Li^(2+) are examples of atoms or ions with one electron each . The energy of such atoms when in the n-th energy state (according to Bohr,s theory , n=1,2,3…. =principal quantum number ) is E_n =(13.6 Z^2)/(n^2) eV (1 eV =1.6xx10^(-19)J) . For the ground state ,n=1 . in order to raise the atom from the ground state to n=f , the suitable incident light should have a wavelength given by lambda=(hc)/(E_f-E_1) . But the atom cannot stay permanently in the f-energy state, ultimately , it comes to the ground state by radiating the extra energy , E_f-E_1 as electromagnetic radiation . The electron of the atom comes from n=f to n=1 in one or more steps using the permitted energy levels . As a result there is a possibility of emission of radiation with more than one wavelength from the atom. Planck's constant =6.63 xx10^(-34)J*s and velocity of light c=3xx10^(8)m*s^(-1) . For what wavelength of incident radiation He^+ ion will be raised to fourth quantum state from ground state?

H, He^(+), Li^(2+) are examples of atoms or ions with one electron each . The energy of such atoms when in the n-th energy state (according to Bohr,s theory , n=1,2,3…. =principal quantum number ) is E_n =(13.6 Z^2)/(n^2) eV (1 eV =1.6xx10^(-19)J) . For the ground state ,n=1 . in order to raise the atom from the ground state to n=f , the suitable incident light should have a wavelength given by lambda=(hc)/(E_f-E_1) . But the atom cannot stay permanently in the f-energy state, ultimately , it comes to the ground state by radiating the extra energy , E_f-E_1 as electromagnetic radiation . The electron of the atom comes from n=f to n=1 in one or more steps using the permitted energy levels . As a result there is a possibility of emission of radiation with more than one wavelength from the atom. Planck's constant =6.63 xx10^(-34)J*s and velocity of light c=3xx10^(8)m*s^(-1) . Which among the following differences in the energy levels for a Li^(2+) ion is minimum ?

H, He^(+), Li^(2+) are examples of atoms or ions with one electron each . The energy of such atoms when in the n-th energy state (according to Bohr,s theory , n=1,2,3…. =principal quantum number ) is E_n =(-13.6 Z^2)/(n^2) eV (1 eV =1.6xx10^(-19)J) . For the ground state ,n=1 . in order to raise the atom from the ground state to n=f , the suitable incident light should have a wavelength given by lambda=(hc)/(E_f-E_1) . But the atom cannot stay permanently in the f-energy state, ultimately , it comes to the ground state by radiating the extra energy , E_f-E_1 as electromagnetic radiation . The electron of the atom comes from n=f to n=1 in one or more steps using the permitted energy levels . As a result there is a possibility of emission of radiation with more than one wavelength from the atom. Planck's constant =6.63 xx10^(-34)J*s and velocity of light c=3xx10^(8)m*s^(-1) . Energy of which quantum state of He^+ ion will be equal to the ground level energy of hydrogen ?