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The compound CuCl has ZnS structure and ...

The compound CuCl has ZnS structure and the edge length of the unit cell is 500 pm. Calculate its density (Atomic mass of Cu = 63, Cl = 35.5)

Text Solution

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The correct Answer is:
`5.23"g cm"^(-3)`
Density `(rho)=(ZxxM)/(a^(3)xxN_(0)xx10^(-30))`
Edge length (a) = 500 pm 500
Gram formula mass of CuCl (M) = `63+35.5=98.5 "g mol"^(-1)`
No. of formula units of unit cell (z) = 4 , Avogadro's No. `(N_(0))=6.022xx10^(23)"mol"^(-1)`
`"Density"(rho)=(4xx("98.5 g mol"^(-1)))/((500)^(3)xx(6.022xx10^(23)"mol"^(-1))xx(10^(-30)xx"cm"^(3)))=5.23"g cm"^(-3)`
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