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An element of atomic mass 52 occurs in b...

An element of atomic mass 52 occurs in bcc structure with cell edge length of 288 pm. Calculate the Avodadro's number if density is `7.2gm//cm^(3)`.

Text Solution

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The correct Answer is:
`6.05xx10^(23)mol^(-1)`
`"Density"(rho)=(zxxM)/(a^(3)xxN_(0)xx10^(-30))orN_(0)=(zxxM)/(a^(3)xxrhoxx10^(-30))`
Edge length (a) = 288 pm = 288 , Atomic mass of element (M) = 52 g `mol^(-1)`
No. of atoms per unit cell (z) = 2 , Density of the element `(rho)=7.2"g cm"^(-3)`
Avogadro's number `(N_(0))=(2xx("52 g mol"^(-1)))/((288)^(3)xx(7.2"g cm"^(-3))xx(10^(-30)cm^(3)))=6.05xx10^(23)"mol"^(-1)`
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