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The melting point of RbBr is 682^(@)C, w...

The melting point of `RbBr` is `682^(@)C`, while that of `NaF` is `988^(@)C` . The principla reason that melting point of `NaF` is much higher than that of `RbBr` is that `:`

A

the two crystals are not isomorphous

B

the molar mass of NaF is smaller than that of RbBr

C

the bond in RbBr has more covalent character than the bond in NaF

D

the internuclear distance `(r_(c)+r_(a))` is greater for RbBr than for NaF.

Text Solution

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The correct Answer is:
D
Lattice energy is inversely proportional to inter ionic distance and so is the melting point of a crystalline solid For details, consult additional important questions
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