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CsCl crystallises in body centred cubic ...

CsCl crystallises in body centred cubic lattice. If 'a' is its edge length then which of the following expression is correct ?

A

`r_(Cs^(+))+r_(Cl^(-))=3a`

B

`r_(Cs^(+))+r_(Cl^(-))=(3a)/2`

C

`r_(Cs^(+))+r_(Cl^(-))=sqrt(3)/2 a`

D

`r_(Cs^(+))+r_(Cl^(-))=sqrt(3)a`

Text Solution

Verified by Experts

The correct Answer is:
C
In CsCl, the `Cl^(-)` ion lie at the corners of simple cube and `Cs^(+)` ion at the body centre. Along the body diagonal both `Cs^(+)` and `Cl^(-)` ions touch each other.
Therefore, `1//2` of body diagonal `r_(Cs^(+))+r_(Cl^(-))=sqrt(3)/2a`
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