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Suppose the mass of a single Ag atoms is...

Suppose the mass of a single Ag atoms is 'm' Ag metal crystallises in fcc lattice with unit cell edge length 'a' The density of Ag metal in terms of 'a' and 'm' is:

A

`(4m)/a^(3)`

B

`(2m)/a^(3)`

C

`m/a^(3)`

D

`m/(2a^(3))`

Text Solution

Verified by Experts

The correct Answer is:
A
Density `=("Mass of the unit cell")/("Volume of the unit cell")`
`=("No .of atoms" xx"Mass of each atom")/("Volume of the unit cell")`
`=(4xxm)/a^(3)` (in fcc arrangement no, of atoms `=4`)
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