Home
Class 12
CHEMISTRY
30 g of CH(3)MgBr reacts with excess of ...

30 g of `CH_(3)MgBr` reacts with excess of `CH_(3)CH_(2)CH_(2)OH` forming xg of a gas. What is the value of x?

Text Solution

Verified by Experts

`underset((=119g))(CH_(3)MgBr)+CH_(3)CH_(2)underset(OH)underset(|)(CH_(2))rarrunderset((=16g))(CH_(4)(g))+CH_(3)CH_(2)underset(OMgBr)underset(|)(CH_(2))`
`119g` of `CH_(3)MgBr` evolve `CH_(4)=16 g`
30 g of `CH_(3)` MgBr evolve `CH_(4)=(30g)xx((16g))/((199g))=4g.`
`:.` Value of x=4
Promotional Banner

Similar Questions

Explore conceptually related problems

The IUPAC name of CH_(3)CH_(2)OCH(CH_(3))_(2) is :

Write down the IUPAC name of CH_3CH_2CH_2CH_2OH .

The maximum number of CH_(3)I molecules which will react with CH_(3)NH_(2) is-

Out of CH_(3)CH_(2)COCH_(2)CH_(3) and CH_(3)CH_(2)CH_(2)COCH_(3) which gives iodoform test ?

Do the following conversions :- CH_3CH=CH_2 to CH_3CH_2CH_2OH

(CH_(3))_(3)C-OCH_(3) on reaction with HI gives (CH_(3))_(3)C-I and CH_(3)-OH as the main products and not (CH_(3))_(3)C-OH and CH_(3)-I . Explain.

The IUPAC name of compound CH_(3)-CH_(2)CH(CH_(3))CH_(2)COCl is

Write the IUPAC names of (i) CH_(3)OCH_(2)CH_(2)OH (ii) CH_(3)OCH_(2)OCH_(3) and (iii)

Alkene which forms CH_3COCH_2CH_2CH_2CH_2COCH_3 on ozonolysis is -