`0.44 g` of a monohydric alcohol when added to methylmagnesium iodide in ether liberates at STP `112cm^3` of methane. With PCC,the same alcohol forms a carbonyl compound that answers silver mirror test. The monohydric alcohol is

Explanation

According to the available information:
`{:(ROH+CH_(3)Mglrarr,CH_(4),+ ,(0.44g,11cm^(3),):}`
Molarcular mass of alcohol `= ((0.44g))/((112 cm^(3))) xx (22400 cm^(3)) = 80 g`
Since the alcohol is oxidised by PCC (pyridine chlorochromate or Carry's reagent) to form a carbonyl group which is an aldehyde, the alcohol must be of primary nature. Corresponding to the molecular mass of `88 g "mol"^(-1)` , the alcohol is a teritary pentyl alcohol. The reaction involves is :