Iodoform is prepared by reacting acetone with hypoiodite and not with iodine. How will you account for it ?

Explanation

In the acetone molecules, `alpha`-hydrogen atoms are to be replaced as `H^(+)` ions by the `I^(+)` ions made available by hypoiodite (say NaOI). Iodine being non-polar innature , does not provides `I^(+)` ions made available by hypoiodite (say `NaOI`), Iodine being non-polar in nature, does not provide `I^(+)` ion for the attack.
`underset("Acetone")(CH_(3)COCH_(3)) + underset("Hypoiodite ion")(3IO^(-))rarrunderset("Tri-iodoacetone")(CI_(3)COCH_(3))+3OH^(-)`