An organic compound [A], whose molecular formula is `C_(3)H_(6)O`, gives iodoform reaction and forms compound [B]. Compound [B], when heated with silver powder, converts into compound [C}. Compound [C] reacts with dil. Sulphuric acid and mercuric sulphate to obtain compound [D], which gives Aldol condensation reaction. Write down the names of all compounds from [A] to [D] and also write the chemical equations for each step.

Explanation

The compound [A] can be either an aldehyde or a ketone. Since it gives iodoform test, it is a methylketone and is propanone. As a result of iodoform reaction, the compound [A] gives iodoform [B]. When heated with silver poweder, iodoform changes into ethyne [C]. Ethyne upon hydration in the acidic condition gives ethanal [D] which responds to Aldol condenastion. The chemical reactions involved are lised.
`underset("Propanone [A]")(CH_(3)-overset(O)overset(||)(C)-CH_(3))overset(I_(2)//Na_(2)CO_(3))rarrunderset("Iodoform [B]")(CHI_(3))overset(Ag)underset("Heat")rarrunderset("Ethyne [C]")(CH-=CH)overset(H_(2)O)underset(HgSO_(4)//H_(2)SO_(4))rarrunderset("Ethanal [D]")(CH_(3)CHO)overset("Aldol Condensation")underset("NaOH")rarrunderset(3-"Hydroxybutanal")(CH_(3)CH(OH)CH_(2)CHO)`