Home
Class 12
BIOLOGY
A tall true breeding garden pea plant is...

A tall true breeding garden pea plant is crossed with a dwarf true breeding garden pea plant. When the `F_(1)` plants were selfed the resulting genotypes were in the ratio of

A

3:1-dwarf: tall

B

1:2:1- tall homozygous : tall heterozygous : dwarf

C

1:2:1- heterozygous : tall homozygous : dwarf

D

3:1-tall : dwarf

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

A true breeding plant is

A yellow seeded true breeding Pea plant is crossed with green seeded true breeding plant. F_(1) plants were yellow seeded showing that allele for yellow colour is

If two hybrid tall pea plant is crossed then what will be the percentage of pure tall plant in F_1 generation?

Pure tall pea plant with round seeds is crossed with pure dwarf pea plant with wrinkled seeds . The probability of genotype ttRR in F_2 generation is

TT Pea plant is crossed to tt plant. F_(2) generation will have

A yellow round seeded Pea plant is crossed with green wrinkled seeded pea plant. Four phenotypes appeared in the progeny in the ratio of 1:1:1:1. The genotype of the two are

A tall pea plant with round seeds (TTRR) is crossed with a dwarf wrinkle seeded plant (ttrr). F_(1) has tall plants with rounded seeds. What is the proportion of dwarf plants with wrinkled seeds in F_(2) generation

A pure breeding plant with red dot on leaves was crossed with pure breeding white dotted plants. The heterozygotes have both red and white dots. On self pollination of F_(1) , what fraction of plants show both red and white dots on leaves

A plant with a genotype Aa Bb is crossed with a plant having the genotype aa bb. The genotype of F_(1) would be

A homozygous tall pea plant with green seeds is crossed with a dwarf pea plant with yellow seeds. (i) What would be the phenotypeand genotype of f_(1) ? (ii) Work out the phenotypic ratio of F_(2) generation with the help of a punnet square.