Home
Class 12
PHYSICS
In the circuit shown, the capacitor is i...

In the circuit shown, the capacitor is initially uncharged. The switch S is closed at t = 0. Time after which voltage across capacitor and resistor are equal is:

A

`RCln""(1)/(2)`

B

`RCln2`

C

`RCln""(3)/(2)`

D

RC

Text Solution

Verified by Experts

The correct Answer is:
B
`V_(C)=V(1-e^(-t//RC))`
`(V)/(2) =V (1-e^(-t//RC))`
`e^(-t//RC)=1-(1)/(2)=(1)/(2)`
`t=RCln2`
Promotional Banner

Similar Questions

Explore conceptually related problems

In the circnit shown, capacitor is initially uncharged till the switch is turned on at time t= 0 . Then

The switch is closed at t=0. Find time after which voltage across capacitor becomes 50 V. (take ln 2 = 0.6)

In the circuit shown, the capacitor C_1 is initially charged with charge q_0 . The switch S is closed at time t = 0 . The charge on C_2 after time t is

In the circuit shown key is closed at t=0 with capacitor initially uncharged.

In the circuit shown in figure-3.244, the battery is an ideal one with emf V. The capacitor is initially uncharged. The switch S is closed at time t=0. (a) Find the charge Q on the capacitor at time l (b) Find the current in branch AB at time just after closing the switch.

In the circuit shown in Figure, the battery is an ideal one, with emf V. The capacitor is initially uncharged. The switch S is closed at time t = 0 . (a) Find the charge Q on the capacitor at time t. (b) Find the current in AB at time t. What is its liniting value as t rarr oo : .

In the circuit shown in figure, the capacitor is charged with a cell of 5V .If the switch is closed at t=0 , then at t=12s , charge on the capacitor is

In the circuit as shown in figure the switch is closed at t = 0 . A long time after closing the switch

In the circuit shown initially C_1, C_2 are uncharged. After closing the switch