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In the following RC circuit, key is kept...

In the following RC circuit, key is kept closed for a long time and then it is opened at t=0. What is the current in resistance 2R after time `t=(3RC)/(2)?`

A

`(2V)/(9Rsqrte)`

B

`(2V)/(3Rsqrte)`

C

`(2V)/(9R)e^(-2//3)`

D

`(4V)/(9R)e^(-2//3)`

Text Solution

Verified by Experts

The correct Answer is:
A
Charge on capacitor in steady state (key closed)
`=(2CV)/(3)`
When key is opened `q = (2CV)/(3) e^(-t//3RC)`
`i=(-dq)/(dt) =(2CV)/(3)xx(1)/(3RC)e^(-t//3RC) =(2V)/(9R)e^(-t//3RC)`
`i=(2V)/(9R) e^(-1//2) =(2V)/(9R sqrt(e))`
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