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A capacitor of capacitance 2muF is conne...

A capacitor of capacitance `2muF` is connected in a circuit as shown. Both cells have emf 2.5V and internal resistance `0.5Omega`. Find the charge on capacitor (in `muC` )

Text Solution

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In steady state, there is no current in the branch of capacitor. Current in outer loop `=(2.5)/(2+0.5) =1A`
`therefore` Voltage across capacitor `= epsi -lr +2.5=2.5-1(0.5)+2.5=4.5V`
`therefore Q= CV =2(4.5) =9 mu C`
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